2007-10-06 14:36:29 · 6 answers · asked by deannahndrsn 2 in Science & Mathematics ➔ Mathematics
3√[3]+2√[27]-√[12]
= 3√[3]+6√[3]-2√[3]
= 7√[3]
2007-10-06 14:40:33 · answer #1 · answered by sahsjing 7 · 1⤊ 1⤋
First simplify the square roots. For part of the answer, sq root of 27 is sq root of 9 times sq root of 3 - since sq root of 9 is 3, then 2 sq root 27 is 2 x 3 sq root of 3. Do the same thing to simplify the sq root of 12, and you'll be able to just add them up.
Sahsjing does you no favor by just doing your homework for you - I doubt that you'll have access to Yahoo Answers during your exams.
2007-10-06 21:41:25 · answer #2 · answered by Judy 7 · 0⤊ 1⤋
Well, first you need to make the numbers under the radicals all the same... for example (square root of 27 is going to break down to square root of 9 and 3... square of 9 breaks down to 3 so 2 x 3= 6) and (square root of 12) breaks down to square root of 4 and 3... square root of 4 breaks down to 2(square root 3).
So it's 3(square root 3) + 6 (square root 3) - 2 (square root 3)
Just do PEMDAS now.
Sorry, I don't know how to make the square root sign..
2007-10-06 21:43:24 · answer #3 · answered by mysterygirl 3 · 0⤊ 0⤋
Simplify it...
sqrt(27) = sqrt(9*3) = 3 sqrt (3)
sqrt(12) = sqrt(4*3) = 2 sqrt (3)
2007-10-06 21:39:41 · answer #4 · answered by feanor 7 · 0⤊ 0⤋
Remember= P E M D A S or Please Excuse My Dear Aunt Sally order of operations
2007-10-06 21:43:15 · answer #5 · answered by mycus2000 2 · 0⤊ 0⤋
they all hab the same root â3.. change them to their simplest form.. n simplify.
2007-10-06 21:42:33 · answer #6 · answered by GalNextDoor 4 · 0⤊ 0⤋