30k^3 / 6k.
= 5k^2
2007-10-06 12:39:15
·
answer #1
·
answered by harry m 6
·
0⤊
0⤋
30k^3/6k
=5k^3/k^1
=5k^(3-1)
=5k^2
The coefficients 30 and 6 are impartial to the variable k. 6 goes into 30 5x. You can then subtract the exponents due to your exponent law that states that if you are dividing two powers with the same base, you can subtract the exponents. Thus you are left with 5k^2.
2007-10-06 12:42:03
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
30k^3 = 27000k/6k = 4500k
2007-10-06 12:42:00
·
answer #3
·
answered by Eduardo (lalo) Leal 2
·
0⤊
0⤋
= (30 k ^2)/6
= 5k^2
2007-10-06 12:39:42
·
answer #4
·
answered by ron1999 2
·
0⤊
0⤋
30k^3/6k
=5k^2.ANS.
2007-10-06 12:39:37
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
30k^2
the k in the denometer cancells out one of the ks in the numerator.
2007-10-06 12:40:20
·
answer #6
·
answered by Tomboy with girly tendencies 4
·
0⤊
1⤋
5k^2
2007-10-06 12:42:19
·
answer #7
·
answered by ironduke8159 7
·
0⤊
0⤋
5k^2
2007-10-06 12:42:02
·
answer #8
·
answered by Crazy and Lovin It 4
·
0⤊
0⤋