Okay i've tried already 4 times.. And i have one more try ( since i do my university assignments on the computer) I really don't understand i've done everything that book told me, but im missing something.. Can someone please show me step by step You don't need to give me the anwser... you can place different numbers if you like. Please help thanks :(
Combustion of C12H22O11(s) (sucrose or "table sugar") produces CO2(g) and H2O(l).
When 2.37 g of sucrose is combusted in a constant volume (bomb) calorimeter, 39.1 kJ of heat is liberated.
Calculate deltaE for the combustion of 7.50g of sucrose.
2007-10-06 11:24:25 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Delta E refers to the energy released when 1 mole is burned. At constant volume, delta E is equal to the heat, because no other energy is released. Convert the 2.37 g to moles using the molar mass calculated from the periodic table. Then, divide the heat released by the number of moles, and you have the delta E.
2007-10-06 18:16:43 · answer #1 · answered by FrogChemist 3 · 0⤊ 0⤋
Let sucrose be called S.
7.50gS x 39.1kJ/2.37gS = 123 kJ
2007-10-06 12:33:09 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋