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A dockworker loading crates on a ship finds that a 19 kg crate, initially at rest on a horizontal surface, requires a 84 N horizontal force to set it in motion. However, after the crate is in motion, a horizontal force of 50 N is required to keep it moving with a constant speed. Find the coefficients of static and kinetic friction between crate and floor.

2007-10-06 10:53:37 · 1 answers · asked by swimchic632 2 in Science & Mathematics Physics

1 answers

in order to get the crate to move, static friction must be less than or equal to 84N

Friction = μ (normal force)

the normal force, in this case, is equal to the weight of the crate.

normal = weight
normal = mg
normal = 19 * 9.8
normal = 186.2N

84N = μ (186.2)
μ =~ 0.451


50N is the force to keep the crate moving at a constant speed. Since the crate is not accelerating, the forces are balance. That means the kinetic friction force must be also 50N

friction = μ (normal force)
50 = μ (186.2)
u =~ 0.269

2007-10-06 11:04:11 · answer #1 · answered by      7 · 0 0

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