For the function y=(x-6)(x+8)(4x-2)?

Question

what are its y intercepts and x intercepts and when x approaches infinity does y approach positive or negative infinity and same question with x? please help

Answer 1

To find the x-intercepts, find where y = 0.

x - 6 = 0
x + 8 = 0
4x - 2 = 0

x-intercepts are 6, -8, and 1/2



The y-intercept is where x = 0. Just plug in 0 for x.
-6 * 8 * -2 = 96, the y-intercept.

y approaches both negative inifinity and positive infinity for all x. And x approaches negative and positive infinity for all y.

If you were to graph this, it would look sort of like an s turned clockwise.

Answer 2

Geeezzz Dewd. Look at the equation. When x=0 then
y=(0-6)(0+8)(4*0 -2)=(-6)(8)(-2)=96 is the y intercept..
The x intercepts (when y=0) are at x=6 (which makes the 1'st term 0), x=-8 (the 2'nd term is 0) and x = 1/2 (the 3'rd term is 0).
It's pretty obvious that, as x increases without bound, so does y And as x decreases without bound, y decreases without bound.

Doug