displayed formula of the organic products of the reaction of ethanol with the following?

Question

ethanoic acid with an acid catalyst(such as concentrated h2so4)
Benzoyl chloride, c6h5c0cl
propanoyl chloride
hexanoic acid with an acid catalyst as in first and name them

Answer 1

CH3COOCH2CH3 - ethyl ethanoate

(CH)5COOCH2CH3 - ethyl benzoate

CH3CH2COOCH2CH3 - ethyl propanoate

CH3CH2CH2CH2CH2COOCH2CH3 - ethyl hexanoate

NB
1. The acid/chloride functional group is renamed '-oate'.
2. The alcohol functional group is renamed '-yl'
3. The ester functional group is formed in every case.
4. The acid/alcohol reaction eleminates 'water' from the reaction and the catalyst remains unchanged.
5. The -oyl chloride/alcohol reaction eliminates hydrogen chloride.
6. The general nomenclature(name) for the formed esters is always '-yl - oate'.

Answer 2

Hello

Ethanol reacting with ethanoic acid gives you ethylethanoate and water.

Equation is:

C2H5OH + CH3 COOH ~~~> CH3-CO-C2H5 + H2O

(The trick to get the product of a reaction between a carboxylic acid and an alcohol is to remove OH group from each reactant and then join them. Like here, you remove OH from ethanol and OH from ethanoic acid and than join them to give you ethylethanoate.)

Reaction of ethanol with benzoyl chloride gives you ethylbenzoate and water.

Equation is:

C2H5OH + C6H5COCl ~~~> C6H5-CO-C2H5 + H2O

Here what you do is that you remove OH from the alcohol and Cl from the acylchloride which is benzoyl chloride in this question.

Reaction of ethanol with propanoyl chloride:

This will use the same principle as the previous reaction.

The products for this reaction will be ethylpropanoate and water.

Equation is:

C2H5OH + C2H5COCl ~~~> C2H5-CO-C2H5 + H2O

Here again you remove OH from the alcohol and Cl from the acylchloride that is propanoyl chloride. However do note that this technique is only for reactions between alcohols and acylchlorides.

For the last reaction, you will have to use the same procedure as with the first reaction I gave. You remove OH group from the alcohol and from the carboxylic acid. Then join the two. Also note that this technique is for reactions between alcohols and carboxylic acids.

The products for this last reaction will be ethylhexanoate and water.

Equation is:

C2H5OH + C5H11COOH ~~~> C5H11-CO-C2H5 + H20

Something else to note: apart from water, all the products formed are called esters. One of their characteristics is that they are all sweet smelling compounds. It makes it easy to identify them in practicals.

I hope this helps.

Answer 3

CH3COOCH2CH3 - ethyl ethanoate CH3COOCH(CH3)2 - 2-propyl ethanoate CH3COOCH2CH2CH3 - (a million)-propyl ethanoate CH3COOCH(CH2)5 - cyclohexyl ethanoate NB a million. The acid sensible group is renamed '-oate' . 2. The alcohol sensible group is renamed '-yl' 3. The nomenclature (call) is often - '-yl - oate'. 4. The chemical bonding between the two sensible communities is the 'ester' linkage.

Answer 4

with ethanoic acid= CH3COOCH2CH3. ETHYLETHANOATE.
with benzoylchloride = C6H5COOCH2CH3.ETHYLBENZOATE

withpropanoylchloride = CH3CH2COOCH2CH3.ETHYLPROPANOATE
with hexanoic acid = C5H11COOCH2CH3.ETHYLHEXANOATE.

Answer 5

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