A 110 kg piano is placed on an incline of 35 degrees. the coefficient of friction between the piano and the incline is .13. What is the force of friction on the piano? What is the piano's acceleration down the incline?
im not sure what to do, for the force of friction i have two different answers, i got 80N and 114.79N.. i dont know if they're right.. then i have no idea how to figure out the acceleration..
please help!!
2007-10-06 06:01:51 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Force of friction is mg multiplied by .13 and cosine of 35, which should be around 114.7 N. I do not know how you got 80 N. For finding acceleration you have to find out the net force Force due to gravity is mg multiplied by sine 35. The force of friction is in the opposite direction. So you subtract the force of friction from force of gravity both acting tangential to the plane but in opposite direction. Divide the result by mass 110 Kg and you would get acceleration. It should be about 0.4g.
2007-10-06 06:50:44 · answer #1 · answered by Let'slearntothink 7 · 0⤊ 0⤋