If the sum of three consecutive odd integers is 69, what is the largest odd integer?
2007-10-06 05:50:51 · 8 answers · asked by Monique L 2 in Science & Mathematics ➔ Mathematics
(x)+(x+2)+(x+4)=69
Find x, and then add four to it.
2007-10-06 05:53:33 · answer #1 · answered by Anonymous · 0⤊ 0⤋
A simple solution is to divide 69 by 3 and add 2 to the answer to get the largest integer, subtract 2 for the smallest, and the answer is the middle integer, therefore
integers are 21,23,25 and the largest is 25.
2007-10-06 12:57:20 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Remember that odd numbers are 2 apart just like even numbers. 3,5,7 If 3=x then 5=x+2 and 7=x+4
Not x x+1 and x+3 If x=3 x+1=4 and x+3=6. This would not be right.
You need (x)+(x+2)+(x+4) = 69 You would still be operating with 3 consecutive odd numbers if the first one was odd.
Hope this helps!
2007-10-06 13:00:15 · answer #3 · answered by Ed S 4 · 0⤊ 0⤋
If x is the first odd integer, then the next is x + 2 and the next is x + 4
So 3x + 6 = 69
3x = 63
x = 21
So, 21, 23 and 25 are the odd numbers and 25 is the largest.
2007-10-06 12:55:56 · answer #4 · answered by Swamy 7 · 1⤊ 0⤋
The three consecutive odd integers are;
21,23 and 25.
So,the largest odd integer would be;
25!
2007-10-06 12:54:53 · answer #5 · answered by Anonymous · 0⤊ 0⤋
lowest number = x
x + (x+2) + (x +4) = 69
3x + 6 = 69
3x = 69 - 6 = 63
x = 63/3 = 21
numbers are 21, 23, 25
2007-10-06 13:05:53 · answer #6 · answered by mechnginear 5 · 0⤊ 0⤋
(2x-1)+(2x+1)+(2x+3)=69
2x-1+2x+1+2x+3=69
6x+3=69
6x=66
x=11
21+23+25=69
answer 25
2007-10-06 12:56:36 · answer #7 · answered by wwwtoha 3 · 0⤊ 0⤋
25!!
2007-10-06 12:56:58 · answer #8 · answered by JC Zac 3 · 0⤊ 0⤋