A crate of mass 10.7 kg is pulled up a rough incline with an initial speed of 1.50 m/s. The pulling force is 190 N parallel to the incline, which makes an angle of with the horizontal. The coefficient of kinetic friction is 0.450, and the crate is pulled 4.40 m.
a) How much work is done by gravity?
b) How much mechanical energy is lost due to friction?
c) How much work is done by the 190 N force?
d) What is the change in kinetic energy of the crate?
e) ) What is the speed of the crate after it has been pulled 4.40 m?
2007-10-06 05:31:55 · 1 answers · asked by snow200098 2 in Science & Mathematics ➔ Physics
angle is 21.4 degrees. sorry
2007-10-06 05:59:57 · update #1
without value of the angle 'alpha' of the incline with horizontal none of the question can be answered except c). The answer to C 190x4.40 Joules.Net force acting on the crate is 190 N - m g sin (alpha) - 0.450xmg cos (alpha). If you proceed on these lines you would get answers to all questions
2007-10-06 05:57:21 · answer #1 · answered by Let'slearntothink 7 · 0⤊ 0⤋