10 points to get if u solve correctly?

Question

f(x)= (8x-2)/ (x^2-1x-30)
find the following
vertical asymptotes
horizontal asymptotes
and the x-intercepts

Answer 1

Vertical asymptotes are where the denominator goes to 0

f(x) = (8x-2) / (x² - x - 30)
f(x) = 2(4x-1) / [(x+5)(x-6)]

There are two vertical asymptotes:
x = -5
x = 6

Horizontal asymptotes are the limits as x goes to infinity and -infinity
f(x) = (8x-2) / (x² - x - 30)


As x goes to infinity:
f(x) goes to 0

As x goes to -infinity:
f(x) goes to 0

Horizontal asymptote: y=0

x-intercepts are where f(x)=0
(8x-2) = 0
8x = 2
x = 1/4
x-intercept: (1/4, 0)

Answer 2

f(x)= (8x-2)/ (x^2-1x-30)
= 2(4x-1)/[x-6)(x+5)]
Vertical asymptotes are x=6 and x =-5 because they make the denominator zero.

The x-axis is a horizontal asymptote because lim x--> infinity f(x) = 0.

x -intercept is (.25,0) because .25 makes numerator = 0.