also which of the two compounds has a broadened trough(peak) at this wavenumber?
2007-10-06 04:26:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The keto functional group (C=O) is responsible for the absorption at 1740 cm^-1 in both molecules.
However, in ethanoic acid the absorption at 1740 cm^-1 is slightly broader, due to the adjacent C-O bond, which is not present in propanone.
In ethanoic acid there will be a very broad absorption at approximately, 2500 - 3000 cm^-1, owed to the presence of a hydroxy group (O-H). This is very characteristic of carboxylic acids, of which ethanoic acid is one. This very broad absorption is not present in propanone as there is no hydroxy (O-H) functional group.
2007-10-06 06:35:55 · answer #1 · answered by lenpol7 7 · 1⤊ 0⤋
The bond is C=O, and ethanoic acid's trough is wider.
2007-10-06 04:35:50 · answer #2 · answered by lizard_magic 1 · 0⤊ 0⤋
why bother, use super glue instead.
2007-10-06 04:39:31 · answer #3 · answered by MICHAEL K 2 · 0⤊ 0⤋
007.
2007-10-06 04:31:51 · answer #4 · answered by captbullshot 5 · 0⤊ 0⤋