I have two triangles inside one another, and I don't know the bases of either of them. The base ratio is 4:9. I know that the sides of the smaller triangle are 4 and 3.2 and the sides of the larger triangle are 9 and 7.2.
Does anybody have ANY idea how I can find out the bases of the two triangles?!?
2007-10-06 03:31:15 · 3 answers · asked by Kess 2 in Science & Mathematics ➔ Mathematics
Neither are right angles, and I can't find out how to work out the bases with just the sides and no angles.........
2007-10-06 03:59:37 · update #1
If you are using book 10A, page 363, ex 14D question then I shall help:
3b.) APQ : ABC , AP = 4 , AB = 9 so ratio is 4:9 . Triangles are similar therefore PQ:BC must be 4:9
3c.) area APQ [over] area ABC
ratio of sides = 4:9
so ratio of volumes = (4:9) [squared]
so 4 [over] 9 [all in one big bracket, squared] = 16 [over] 81
so answer is 16 : 81
2007-10-06 22:03:15 · answer #1 · answered by Megan 2 · 0⤊ 0⤋
I'm assuming these aren't necessarily right triangles.
I don't think there is sufficient information to determine the bases. It does sound like the two triangles are similar (the ratios of the other sides are 9:4 as well). If you know the base of one, you can find the base of ther other.
2007-10-06 03:37:54 · answer #2 · answered by SoulDawg 4 UGA 6 · 0⤊ 0⤋
how about the pythagorean theorm
2007-10-06 03:34:28 · answer #3 · answered by Mojo124 1 · 0⤊ 0⤋