i can't solve 6(-u-5)+8(2u+1)
Tell me how plz
2007-10-04 23:57:39 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
distribute so its 6(-u) - 6(5) + 8(2u) + 8(1), multiply then add or subtract as needed.
the best way to do it is to look in your book and learn on your own
2007-10-05 00:16:18 · answer #1 · answered by Katie 3 · 0⤊ 0⤋
First get rid of the bracket by multiplying out:
-6U-30+16U+8=0
Add the the unknown terms and add all the constants:
10U-22=0
Take the 22 over to the other side but dont forget to change the sign:
10U=22
Then just divide by ten both sides:
U=2.2
:)
2007-10-05 07:27:03 · answer #2 · answered by Faz 4 · 0⤊ 0⤋
6(-u-5)+8(2u+1)
= -6u - 30 + 16u + 8
= -6u + 16u -30 +8
= 10u - 22
10u = 22
u = 22/10
u = 11/5
2007-10-05 10:30:40 · answer #3 · answered by evalinz 2 · 0⤊ 0⤋
6(-u-5)+8(2u+1)
You can simplify it but you can't solve it because it is not an equation, does not equal anything.
.
2007-10-05 07:43:21 · answer #4 · answered by Robert L 7 · 0⤊ 0⤋
6(-u-5) + 8(2u+1)=
-6u-30 + 16u+8=
10u - 22 ANSWER
2007-10-05 09:42:38 · answer #5 · answered by fivestring46 4 · 0⤊ 0⤋
Just a note: Follow Katie's example, not Faz's. You cannot "solve" a string of numbers without an equals sign in the question.
FYI: simplified I get
-6u-30+16u+8
10u-22
But I may be wrong, I wrote this is about 10 seconds...
2007-10-05 09:35:14 · answer #6 · answered by Anonymous · 0⤊ 0⤋