A pyramid has a square bottom with an area equal to 64 meters. The height of the pyramid is 7 meters.?

Question

If you startt at the top of the pyramid and slide all the way down the middle of one of the four sides,how many feet will you move.
*I applied the pythagorean theormem to the pramid. Then I applied it to the square.Do I add both answers to find out how many feet will I move?

Answer 1

The pythagorean therom only works on Right Triangles.

The base of the pyramid is 8m X 8m, but you only need to go 4m from the middle of any side to get to the center of the base. Therefore 4m is the length of one of the sides. The length of the other side comes from the height, 7m.

Pythagoras says the sum of the square of the 2 sides is equal to the square of the hypotenuse. In this case the hypotenuse is the distance you would travel if you slide down any one of the sides to the middle of any side (on the ground). Sooo 4^2 + 7^2 = 65

The square root of 65 is about 8.0622577
So you'd slide 8.0622577 m

Change meters to feet by multiplying by 3.28ft/m.

You should get 8.06m X 3.28ft/m = 26.44 ft

Answer 2

You slide down the hypotenuse of an inscribed triangle. The height is 7m; the base is 4m; the hypotenuse is √(49+16) = √65 = 8.0623m × 3.28084 ft/m = 26.451 ft.