In an election between two candidates, 840 votes were cast. If the winner received 310 more than the loser, hom many votes did the loser receive?
please show work. thank you
2007-10-04 14:31:11 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x = number of votes the loser got
x + 310 = number of votes the winner got
x + x + 310 = 840
2x + 310 = 840
2x + 310 - 310 = 840 - 310
2x = 530
2x/2 = 530/2
x = 265
So, the loser received 265 votes.
2007-10-04 14:36:23 · answer #1 · answered by Cassy1122 4 · 0⤊ 0⤋
Let x be the number of votes that the loser get. therefore winner will be x+310.
x+x+310=840
2x+310=840
2x=530
x=265
loser get 265 votes
winner get 575 votes
add back the total is 840 votes.
2007-10-04 21:39:08 · answer #2 · answered by BretHitmanHart 1 · 0⤊ 0⤋
w = 310 + L
w + L = 840
(substitute w with '310 + L')
310 + L + L = 840
310 + 2L = 840
-310 -310
2L = 530
2L/2 = 530/2
L= 265
The loser got 265 votes
2007-10-04 21:37:39 · answer #3 · answered by Abercrombie_Hippie 2 · 0⤊ 0⤋
x = loser
x + 310 = winner
x + (x+310) = 840
2x +310 = 840
2x = 530
x = 265
The loser received 265 votes
The winner received 575 votes
2007-10-04 21:37:39 · answer #4 · answered by nathanr20 1 · 0⤊ 0⤋
winner got 575
loser got 265
w+l=840
diff 310
if tie, both would get 420
1/2 the diff is 155
add 155 to W and subtract 155 from L
420+155=winners tot=575
420-155 losers tot=265
2007-10-04 21:40:17 · answer #5 · answered by Mike 7 · 0⤊ 0⤋
x+y=840
x=y+310
=>y+310+y=840
2y+310=840
2y=530
y=265
x=265+310
x=575
2007-10-04 21:43:42 · answer #6 · answered by Anonymous · 0⤊ 0⤋