Just substitute the given answer (-4 and -2), into the given equation.
|3(-4) + 8|
|-12 + 8|
|-4| = 4
4 isn't 20, so there you go. -4 doesn't work.
The | | just means absolute value, which means you consider just the number, not the sign. Basically everything negative becomes positive, and everything positive stays positive.
In the case of the second equation, it looks like -2 works out to be right.
2007-10-04 13:25:21
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answer #1
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answered by Fuji 2
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|x| = absolute value of x, which means the absolute distance of x from 0, neglecting whether x is a negative or a positive number.
if x<0 then |x|=-x
if x=0 then |x|=0
if x>0 then |x|=x
For example |5|=5; |0|=0; |-3|=3
This means that |x| is always greater than 0 or equals to 0, but can't have the value of a negative number.
Replacing x=-4 to the equation
|3x+8| = 20
|3(-4)+8| = 20
|-12+8| = 20
|-4|= 20
4=20
False, -4 is not a solution of the equation.
Replacing x=-2 to the equation
|6+3x|=0
|6+3(-2)|=0
|6-6|=0
|0|=0
0=0
True, -2 is a solution of the equation.
2007-10-04 20:34:42
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answer #2
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answered by M Barto 1
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To determine if something is a solution, just plug it in and see if your statement is true. In these cases:
|3(-4)+8|=20
|-12+8|=20
|-4|=20
4 = 20 FALSE, so this is not a solution.
|6 + 3x| = 0
|6 + 3(-2)| = 0
|6 + -6| = 0
|0| = 0
0 = 0 TRUE, so this is a solution.
2007-10-04 20:23:50
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answer #3
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answered by Mr. Adkins 4
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Subsitute in and evaluate:
|3(-4) + 8| = |-12+8| = |-4| = 4, not a solution since we wanted a result of 20.
|6 + 3(-2)| = |6 + (-6)| = |0| = 0, this is a solution.
2007-10-04 20:23:11
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answer #4
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answered by Scarlet Manuka 7
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i guess substitute x=-4 and x=-2 respectively to check if it is equal to 20 or 0
2007-10-04 20:23:51
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answer #5
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answered by Ross 1
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Just plug in the number where the x is, so:
l3x+8l=20
l3(-4)+8l=20
l-12+8l=20
l-4l=20
4=20. therefore -4 is not a solution
2007-10-04 20:24:54
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answer #6
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answered by katherine g 2
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