is this correct? please help?

Question

7-3(8t-10)=85
+3 +3
7(8t-10)=88
>distribute<
7x8t = 56t
7x-10 = -70

56t + 70 = 88
-70 -70
56t=18
56t/56 18/56
t= .3

i know this probably isnt correct
im in algebra 1 in case that helps at all?

pleeeese help

Answer 1

As written:

7-3(8t-10)=85

subtract 7 from both sides

-3(8t-10)=78

divide both sides by -3

8t-10=-26

add 10 to both sides

8t=-16

divide both sides by 8

t=-2

Check work:

7-3(8(-2)-10)=85

7-3(-16-10)=85

7-3(-26)=85

7-(-78)=85

85=85

TRUE

Answer 2

7-3(8t-10)=85
muliply the 3 by the terms inside the ()
7 - (24t - 30) = 85
Now get rid of the ()
7 - 24t + 30 = 85
Move all t to the right and all number to the left
7 + 30 - 85 = 24t
-48 = 24t
divide by 24
-2 = t

56t + 70 = 88
56t = 88 - 70
56t = 18
t = 18/56 correct
t = 9/28

Answer 3

no the answer is incorrect you will solve your problem like this

7-3(8t+-10)=85
to the distributive property which leaves you with
7-24t+30=85
*** you have a plus 30 becaue a + and a - equals - and a - plus a - is a + (-3*-10) 30
combine like terms which are 7 and 30
-24t+37=85
subtract 37 from both sides which leaves you with
-24t=48
divide both sides by -24, which leaves you with
t=-2

7-3(8*-2+-10)=85


56t+70=80
just subtract 70 from both sides which leaves you with
56t=10
divide both sides by 56 which leaves you with
10/56 which reduces to 5/28

Answer 4

yes it is correct