2n + (2n + 2) + (2n + 4) = 18
6n = 12
n = 2
4 , 6 , 8 is answer
2007-10-07 21:30:04
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answer #1
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answered by Como 7
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4+6+8=18
2007-10-04 13:10:05
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answer #2
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answered by anna 1
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divide 18 by 3
6 is the mean of the 3 numbers
so 4+6+8=18
2007-10-04 13:10:25
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answer #3
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answered by X_nOmAd_oo57-ha 3
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x = first even integer
x + 2 = second even integer
x + 4 = third even integer
Add the expressions above (sum of ....)
x + x+2 x+4 = 18
Combine similar terms:
3x + 6 = 18
Subtract both sides of the equation by 6:
3x = 12
Divide both sides of the equation by 3
x = 4 (first even integer)
x + 2 = 6 (second even integer)
x + 4 = 8 (third even integer)
2007-10-04 13:13:04
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answer #4
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answered by edith p 3
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let: n1= x+1
n2= x+2
n3= x+3
n1+n2+n3=18
x+1+x+2+x+3=18
3x+6=18
3x=18-6
3x=12 divide both sides by 3 to get the value of x
x=4 :)
2007-10-04 13:11:59
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answer #5
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answered by Ross 1
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4, 6 , 8
2007-10-04 13:09:38
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answer #6
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answered by mathmos_man 1
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x+(x+2)+(x+4) = 18
3x + 6 = 18
3x = 12
x = 4
(x+2) = 6
(x+4) = 8
Check: 4+6+8 = 18; TRUE
2007-10-04 13:08:40
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answer #7
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answered by "Steve Jobs" 3
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you know that 3 numbers are consecutive.
the 3 numbers add up to 18.
so, n+n+1+n+2 = 18. n is the lowest number. add one to get the next number. add one more, or n+2 to get the largest number.
This is the same as 3n+3=18
2007-10-04 13:09:43
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answer #8
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answered by dogmanice 2
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4, 6, 8
not sure about the equation part.
2007-10-04 13:14:09
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answer #9
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answered by wife2denizmoi 5
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x+(x+2)+(x+4)=18
tke out the brackets to get
x+x+2+x+4=18
3x+6=18
3x=12
x=4
numbers are 4,6,8
2007-10-04 13:11:11
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answer #10
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answered by adriantheace 4
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