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ok these are really simple but my teacher marked these wrong but we get to redo it, so i really want to get this right =]

ok here we go [ btw this is really simple ]

find the mean of
14 14 15 15 15 15 15 15 16 16 16 16 16 16 16 17 17 17 18 19 19 19
((ROUND TO THE NEAREST TENTH))

NEXT........................

find the Lower Quartile and Upper Quartile of ..
13 17 18 20 21 25 26 30

NEXT..

Grade 7 students surveyed to determine how many hours per day they spent on various activties. The results are shown in the circle graph below. About how many hours per day altogether was spent sleeping AND watching tv.

socalizing 13%
watching tv 13%
h.w 8%
eating 8%
sleeping 33%
school 25%



THANK YOU EVERYONE!
[if you could show me how to do it that would be great too. =]

2007-10-04 12:35:03 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

hey everyone thank you so much this REALLY helped i have 1 more question!

it is on here..
http://answers.yahoo.com/question/index;_ylt=AhtJJINIE.pOsljSFl5R7rnsy6IX;_ylv=3?qid=20071004172315AAOILTO

2007-10-04 13:26:46 · update #1

4 answers

356/22=16.18

1st quartile = (17+18)/2 = 17.5
3rd quartile = (25+26)/2 = 25.5

13+33 = 46% = .46*24 = 11.04 hours /day

2007-10-04 12:46:26 · answer #1 · answered by ironduke8159 7 · 0 0

1) Add all of the numbers and divide by the number of numbers (there are 22 of them).
To the nearest 10th means 1 decimal point.
10.59=10.6, 20.43=20.4 etc.
2)13 17 18 20 21 25 26 30
There are 8 values in order.
lower quartile (1/4)8=2
average 2nd and 3rd value
(17+18)/2=17.5
upper quartile(3/4)8=6
average 6th and 7th value
(25+26)/2=25.5

3) 46 % was spent on sleeping and watching TV. There are 24 hrs per day.
46 % of 24 is 24(46/100)=11.04 or approximately 11 hours.

2007-10-04 20:08:20 · answer #2 · answered by cidyah 7 · 0 0

for the gading of 7 students= 56 hours total.

2007-10-04 19:43:58 · answer #3 · answered by X_nOmAd_oo57-ha 3 · 0 0

1) 16.2
2.A) Lower = 17.5
2.B) Upper = 25.5
3) 11.04

2007-10-04 19:44:52 · answer #4 · answered by Allen 1 · 0 0

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