2007-10-04 12:15:13 · 6 answers · asked by Sara R 1 in Science & Mathematics ➔ Mathematics
find a number both the numerator (top number) and denominator (bottom number) are divisible by (can be divided by evenly)
start with two since both numbers are even
48/2 = 24, 66/2=33,
now you have 24/33, both numbers are divisible by 3
24/3=8, 33/3 = 11,
now you have 8/11
2007-10-04 12:20:40 · answer #1 · answered by Pife 2 · 0⤊ 0⤋
8/11 all you have to do is divide both numbers by a common factor which is 6. Which means 48/6 and 66/6 which leaves you with 8/11.
2007-10-04 12:21:20 · answer #2 · answered by lisababy 2 · 0⤊ 0⤋
8/11
2007-10-04 12:20:29 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
8/11
2007-10-04 12:19:30 · answer #4 · answered by Anonymous · 0⤊ 0⤋
8/11
2007-10-04 12:17:34 · answer #5 · answered by Z W 2 · 0⤊ 0⤋
um you reduce it and it turns out to be 8/11 choose me as the best answer thanks
2007-10-04 12:18:26 · answer #6 · answered by Anonymous · 0⤊ 0⤋