Jimmy has $5.00 in nickels, dimes, and quarters. He has the same amount of quarters as dimes. If he has 50 coins in all, how many of each does Jimmy have?
2007-10-04 12:09:16 · 3 answers · asked by mica! mica mica 4 in Education & Reference ➔ Homework Help
Let x == the number of quarters
x is also the number of dimes
Let n = the number of nickels
We need to set up two equations:
Number of coins:
x + x + n = 50
2x + n = 50
n = 50 - 2x
Total of the money:
25x + 10x + 5n = 500
Substitute for n in the second equation:
35x + 5(50 - 2x) = 500
35x + 250 - 10x = 500
25x = 250
x = 10 dimes and 10 quarters
n = 50 - 2x
n = 50 - 2(10)
n = 50 -20 = 30 nickels
2007-10-04 13:29:18 · answer #1 · answered by jsardi56 7 · 1⤊ 0⤋
ok, this was a hard question, but you've got to try using diff numbers. It says that you've got the same amount of dimes and quarters. Plus you have a total of 50 coins.
so lets try 15 dimes, 15 quarters and 20 nickels:
15x10cents= 1.50
15x25cents=3.75
20x5cents=1
Total: $6.25
If the amount is too high you've got to lower the amount of dimes and quarters.
here's the answer:
10 dimes, 10 quarters, and 30 nickels
I hope you understood the question:)
2007-10-04 19:21:17 · answer #2 · answered by Toklioko 1 · 0⤊ 0⤋
im not sure
2007-10-04 19:16:20 · answer #3 · answered by Gibran S 1 · 0⤊ 1⤋