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In the reaction of cobalt(II) chloride and hydrogen fluoride, cobalt(II) fluoride and hydrochloric acid are formed. If 18.6 moles of cobalt(II) fluoride are to be formed what is the mass of CoCl2 needed (grams)? Give an answer accurate to the tenths.

2007-10-04 11:37:02 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Why? Do you ask this problem just for fun?
The formula weight of CoCl2 (Anhydrous) is 129.84 g/mol, while formula weight of CoCl2 (Hexahydrate) is 237.93 g/mol. Thus if you try to use anhydrous CoCl2 and assume 100% productivity, you need: (18.6 mol)*(129.84 g/mol) = 2.42 kg ≈ 2.4kg.

2007-10-05 04:53:23 · answer #1 · answered by Hahaha 7 · 0 0

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