2 - 7i / 1 + 6i + 3 - 5i / 1 + 6i
2007-10-04 11:18:32 · 4 answers · asked by william5000forever 2 in Science & Mathematics ➔ Mathematics
are you posting all of your homework?
2007-10-04 11:28:01 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You have written this poorly. Try using () next time.
(2 - 7i )/(1 + 6i) + (3 - 5i) /( 1 + 6i) = (5 -12i)/(1+6i).
(1+6i)*(a+bi) = 5-12i. test values with FOIL.
2007-10-04 18:46:55 · answer #2 · answered by Thompson-McCain 2 · 0⤊ 0⤋
The denominators are the same, so the sum
simplifies to
(5-12i)/(1+6i).
Now multiply top and bottom of the fraction to get
(5-12i)(1-6i)/ 37 = (-67 - 42i)/37.
so the answer is -67/37 -42/37 i.
2007-10-04 18:32:00 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
(2-7i)/(1+6i)+(3-5i)/(1+6i)
(2-7i)+(3-5i)/(1+6i)=(5-12i)/(1+6i)
2007-10-04 18:52:00 · answer #4 · answered by Anonymous · 0⤊ 0⤋