How many grams of carbon dioxide can form when a mixture of 5.00g ethylene (C2H4) and 3.30g of oxygen is ignited, assuming complete combustion to form carbon dioxide and water?
2007-10-04 11:05:13 · 3 answers · asked by babiiashley 1 in Science & Mathematics ➔ Chemistry
C2H4 + 3O2 ===> 2CO2 + 2H2O
Atomic weights: C=12 H=1 O=16 C2H4=28 O2=32 CO2=44
Let ethylene be called E.
5.00gE x 1molE/28gE = 0.178 mole E
3.30gO2 x 1molO2/32gO2 = 0.103 mole O2
0.178 mole E needs 3(0.178) = 0.534 mole O2, and you haven't got nearly that, so O2 is the limiting reagent--it will run out first. So start again with O2:
0.103molO2 x 2molCO2/3molO2 x 44gCO2/1molCO2 = 3.02g CO2
2007-10-04 11:18:33 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
Boy go do yo studies!!! That way you'll learn somt'n.
2007-10-04 18:08:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋
me either!
2007-10-04 18:08:06 · answer #3 · answered by lover2 1 · 0⤊ 0⤋