Write the equation of the line that passes through the given point and is perpendicular to the given line. Write the answer in slope intercept form
(1, - 5), x= -3/4y + 5
I am so #@%## lost!!
2007-10-04 11:03:37 · 3 answers · asked by calired67 4 in Science & Mathematics ➔ Mathematics
The slope of your line is given by angle alpha with tg(alpha) = -3/4. The perpendicular line will have angle beta = alpha+90. Therefore its slope is tg(beta) = tg(alpha + 90) =
sin(alpha+90)/cos(alpha+90) = cos(alpha)/(-sin(alpha)) = - ctg(alpha) = - 1/tg(alpha). Therefore in your case tg(beta) = 4/3.
The line is then:
y + 5 = (4/3)*(x - 1).
2007-10-04 11:29:11 · answer #1 · answered by fernando_007 6 · 1⤊ 0⤋
The given line has a slope of -4/3 so the slope of the line you want is 3/4, because -4/3*3/4 = -1 means _|_.
Thus your equation will take the form y = 3x/4 + b
Since this line passes through (1.-5) then-5 = 3/4 +b so
b = -5 3/4. So your equation is y = 3x/4 -5 3/4
2007-10-04 11:13:44 · answer #2 · answered by ironduke8159 7 · 1⤊ 0⤋
Im lost 2 if its y=-3/4x+5 id be able to help
2007-10-04 11:14:52 · answer #3 · answered by Kyle 4 · 0⤊ 1⤋