The total cost of Sam’s lunch was $5.40, not including tax. The cost of the drink was one-third the cost of the sandwich and the cost of the French fries was twice as much as the drink. Find the price of each.
2007-10-04 10:10:13 · 5 answers · asked by bollionaire 2 in Science & Mathematics ➔ Mathematics
If:
drink = a
sandwich = 3a
fries = 2a
Therefore:
a + 3a + 2a = 5.40
6a = 5.40
a = 5.40 / 6
a = 0.90
Therefore:
drink = 0.90
sandwich = 3 x 0.90 = 2.70
fries = 2 x 0.90 = 1.80
2007-10-04 10:15:29 · answer #1 · answered by Anonymous · 1⤊ 0⤋
D = cost of drink
S = cost of sandwich
F = cost of French fries
The cost of the drink was one-third the cost of the sandwich
D = S/3
The cost of the French fries was twice as much as the drink
F = 2D
the total cost is 5.40 dollars
D + S + F = 5.40
recal that
D = S/3 ==> S = 3D
and F = 2D
D + 2D + 2D = 5.40
6D = 5.40
D = $0.90
S = 3(0.90)
S = $2.70
F = 2(0.90)
F = $1.80
hope this helps
2007-10-04 17:18:47 · answer #2 · answered by 7 · 0⤊ 0⤋
x= value of sandwhich
drink = 1/3x
French fries = 2 times (1/3)x = 2/3x
x + (1/3)x + (2/3)x = 5.40
x + (3/3) x= 5.40
2x = 5.40
x= 2.70
Sandwich = 2.70, drink = .90, fries =1.80 by substitution into formulas for each item.
2007-10-04 17:17:22 · answer #3 · answered by Treadstone 7 · 0⤊ 0⤋
$5.40 = sandwich + fries + drink
f = 2d
s = 3d
$5.40 = 3d + 2d + d
$5.40 = 6d
d = $0.90
f = 2(.90) = $1.80
s = 3(.90) = $2.70
2007-10-04 17:19:31 · answer #4 · answered by billy 1 · 0⤊ 0⤋
sandwich 2.70
drink.90
fries 1.80
2007-10-04 17:19:03 · answer #5 · answered by dallasmiked 1 · 0⤊ 0⤋