how do i factorise x²=4x=3 and x²-3x and 6y²-7y-5 thankyou
2007-10-04 09:44:10 · 3 answers · asked by garg 1 in Science & Mathematics ➔ Mathematics
Your first selection is messed up.
The second one factors to x(x-3)
The last one factors to
Ax (Bx+C) + D (Bx+C)
in general terms. From the selection,
A*B =6
C*D= -5
D*B+A*C=-7
From the possible candidates (you can't solve this directly), 2x(3x-5)+1(3x-5) or (2x+1)(3x-5)
2007-10-04 09:57:03 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
Did you forget to hit the shift when typing a + sign for the first one? ie should it read x^2+4x+3?
In which case it factorises to
(x+3)(x+1)
The other two are as given in the other answers.
2007-10-04 10:16:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
i'm not sure of the first one but the second one is - x²-3x, {x is common so u use x}, x(x-3). In the second one y is common, 6y²-7y-5, {therefore}, y(6y-7)-5
2007-10-04 09:51:58 · answer #3 · answered by rambos 1 · 0⤊ 0⤋