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Jimmie is building a sandbox that is 12 times as wide as it is deep, and 1m longer than it is wide. It holds 3m^3 of sand when full. The wood cost $24/m^2. How much will the wood cost Jimmie? (btw, there is no top or bottom, just the sides when calculating for the area!!) (that the question...now i got the answer $84....is that right??? if so, can someone confirm that? if not , how would you get the correct answer....) ?? thanks!!

2007-10-04 08:01:31 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

12x *x *(12x +1) = 3

144x^3 + 12x^2 - 3 = 0

solve for x

24$* (2*x*12x +2*x*(12x+1)) = $$$

plug in x

2007-10-04 08:19:57 · answer #1 · answered by nacsez 6 · 0 0

Depth = d
Width = 12d
Length = 12d + 1

Volume = depth * width * length
= d * 12d * (12d + 1)
= 3

so 12d^2(12d + 1) = 3
144d^3 + 12d^2 = 3
144d^3 + 12d^2 - 3 = 0

(4d-1)(36d^2+12d+3) = 0
d = 1/4
so width = 12/4 = 3
and heigth = 3 + 1 = 4


Surface area of box (excluding top / bottom) is
2 * (w*h) + 2 (d*h) or
2 * (3*4) + 2(1/4 * 4) = 24 + 2 or 26

If wood costs $24 / meter square and we need 26 square meters, then we have to spend 24*26 dollars or $624

2007-10-04 08:24:17 · answer #2 · answered by PeterT 5 · 0 0

h = depth
width = 12h
length = 12h+1
So h(12h)(12h+1) = volume = 3 m^3
144h^3 +12h^2 = 48h^3 + 4h^2 -1 = 0
h approximately = .268 m
so width = 12(.268) = 3.216 m
length = 4.216 m
Area = 2hl +2hwl
2(.268*4.216 + .268*3.216 = 14.864 m^2
So cost = 14.864*24 = $356.74

2007-10-04 08:34:55 · answer #3 · answered by ironduke8159 7 · 0 0

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