10 points to whoever help me the most (and no i'm not cheating i'm asking for help/an explanation on how to work it out).
x(3x-2y)+y(3x-4y)
2007-10-04 07:58:04 · 8 answers · asked by Alicia ... 2 in Science & Mathematics ➔ Mathematics
First you have to distribute the number outside the () to the numbers inside:
x(3x-2y)+y(3x-4y)
3x^2 - 2xy + 3xy - 4y^2
then combine like terms
3x^2 +xy - 4y^2
2007-10-04 08:04:23 · answer #1 · answered by busymom_6kids 2 · 0⤊ 0⤋
Well, first off, this is not an equation because there is no equal sign to be found. This is an expression.
We can simplify it by removing the parentheses getting:
3x^2 -2xy +3xy -4y^2
Adding like terms we get
3x^2 + xy -4y^2)
This can be factored to:
(3x+4y)(x-y)
2007-10-04 08:07:21 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
The first thing you have to do is apply the distributive property to the expression; that gives you
3x² - 2xy + 3xy - 4y². Then you combine your like terms and get,
3x² + xy - 4y² this expression can factor into two binomials.
(3x +4y)(x - y) I got it through trial and error.
2007-10-04 08:11:22 · answer #3 · answered by James H 3 · 0⤊ 0⤋
for staters you need to distribite before you can combine like terms...
x(3x - 2y) + y(3x -4y) distribute you x into (3x - 2y) and your y into (3x - 4y)
3x^2 - 2xy + 3xy - 4y^2 now combine your like terms
-2xy + 3xy
3x^2 + xy - 4y^2
you can factor this out
(3x + 4y)(x - y)
depending on what solution they are asking you can go with either one
2007-10-04 08:06:27 · answer #4 · answered by Richard B 3 · 0⤊ 0⤋
multiply 3x -2y by x to get 3x squared-2xy.
multiply 3x-4y by y to get 3xy-4y squared.
combine like terms 3xy & -2xy to get xy.
Answer: 3x squared +xy -4y squared.
2007-10-04 08:08:15 · answer #5 · answered by sugarbabe 6 · 0⤊ 0⤋
Depends what youre doing. If its calculus,
then 0=x(3x-2y)+y(3x-4y)
Then 0=x(3-2[dy/dx]) + (3x-2y) + y(3-4[dy/dx]) +(3x-4y)[dy/dx]
Taking out [dy/dx] -> [dy/dx](-2x -4y +3x -4y] = 3x+3x-2y +3y
-> [dy/dx](x-8y)= 6x +y
[dy/dx]= (6x+y)/(x-8y)
If youre trying to find the roots of a polynomial:
3x^2 -2xy +3xy -4y^2 =0
->3x^2+xy -4y^2=0
->x(3x+y)=4y^2
From there you get:
[x(3x+y)]^(1/2) =2y
It really depens what topic its in.
2007-10-04 08:14:11 · answer #6 · answered by Anonymous · 0⤊ 0⤋
If you go to webmath.com it will give you a detail description how to work it out go to algerbra sole equations.
2007-10-04 08:02:13 · answer #7 · answered by tina d 1 · 0⤊ 0⤋
this isn't an equation or even function this are just agroup of variables that means nothing
so please check it again and resend your question
2007-10-04 08:02:58 · answer #8 · answered by 1101-1001 2 · 0⤊ 0⤋