y= 3(4x)^2+2(4x)
y= 48x^2+8x
dy/dx = 96x+8
or you can take derivative separate
y= 3u^2+2u
dy/du = 6u +2
u= 4x
du/dx =4
but dy/dx = (dy/du)(du/dx) = (6u+2)4 = (6*4x+2)4
= (24x+2)4 = 96x+8
2007-10-04 05:59:26
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answer #1
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answered by Helper 6
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y = 3u^2 + 2u
dy = 6u du + 2 du
but u = 4x and
du = 4 dx
substituting these in dy
dy = 6(4x) (4)dx + 2 (4) dx
dy = 96 x dx + 8dx
dy/dx = 96x + 8
2007-10-04 06:16:14
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answer #2
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answered by mohanrao d 7
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dy/dx = 2(3u) + 2
= 6u + 2
= 24x + 2
= 2( 12x +1 )
smile!
2007-10-04 05:57:41
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answer #3
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answered by rod_dollente 5
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dy/dx = dy/du*du/dx =(6u+2)*(4) = 96x+8
2007-10-04 05:58:27
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answer #4
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answered by nyphdinmd 7
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dy/du = 6u+2
du/dx =4
dy/dx= (dy/du)*(du/dx)
dy/dx=(6u+2)*4
as u want in terms of x
substitue u=4x in dy/dx
dy/dx = {6(4x)+2}*4
dy/dx={24x+2}*4
dy/dx=96x+8
2007-10-04 06:13:31
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answer #5
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answered by Siva 5
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y = a million - e^(-t) get dy/dt dy/dt = 0 - (-a million)e^(-t) dy/dt = e^(-t) x = t + e^(-t) get dx/dt dx/dt = a million - e^(-t) to get dy/dx, divide dy/dt via dx/dt: dy/dx = e^(-t)/(a million-e^(-t)) simplify via multiplying the numerator and denominator via e^(t) dy/dx = a million/(e^(t)-a million)
2016-11-07 06:11:24
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answer #6
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answered by piano 4
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