A roller coaster at an amusement park starts out on a level track 50.0 m long and then goes up a 25.0 m?

Question

incline at an angle of 30 degrees to the horizontal. It then goes down a 15.0 m ramp with an incline of 40 degrees to the horizontal. When the roller coaster has reached the bottom of the ramp, what is its displacement from its starting point? Thank you

Answer 1

Use a bit of trig for the x and y components

x=50+cos(30)*25+cos(40)*15
y=sin(30)*25-sin(40)*15

d=sqrt(x^2+y^2)

x= 83.1
y= 2.86
d= 83.2


j