x^2 + 1 = 7x - 9
x^2 - 7x + 10 = 0
(x - 5) ( x - 2) = 0
x = 5, x = 2
2007-10-04 05:17:23
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answer #1
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answered by Axis Flip 3
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1) y = 7x - 9
2) y = x^2 + 1
Since both of the equations are solved for y, set them equal to each other
x^2 + 1 = 7x - 9
x^2 - 7x + 10 = 0
(x - 5)(x - 2) = 0
x = 5, x = 2
1) y = 7(5) - 9 = 35 - 9 = 26
2) y = 5^2 + 1 = 25 + 1 = 26
When x = 5, y = 26
1) y = 7(2) - 9 = 14 - 9 = 5
2) y = 2^2 + 1 = 4 + 1 = 5
When x = 2, y = 5
2007-10-04 12:35:48
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answer #2
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answered by kindricko 7
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One way to solve simultaneous equations is to insert one equation into the other.
So we know that y=7x-9 and y=x^2+1 so we can replace y with 7x-9.
7x-9=x^2+1
You then need to rearrange the formula so you can solve it. With this one you need to turn it into a quadratic equation because you have an x^2. So move all the values to one side to leave the other side as 0.
x^2+1+9-7x=0
X^2-7x+10=0
Then you have to factorize the equation.
(x-5)(x-2)=0
Now, because you know that it equals zero we know that either (x-5)=0 or (x-2)=0 (because the only way to get 0 as the result of a multiplication is for one of the values to be zero). So we are going to get two results.
if x-5=0 then x=5
if x-2=0 then x=2
So the two results for x are 5 and 2. But remember we still need to work out y. To do that all we need to do is substitute our values into the equation, first 5, then 2.
y=7x-9
If x=5
y=7*5-9
y=26
If x=2
y=7*2-9
y=5
So, all the values for y and x are:
x=5 and y=26
or
x=2 and y=5
2007-10-04 12:24:52
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answer #3
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answered by Atari 2
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y = 7x - 9
y = x^2 +1
Take first equation substitue for y in second equation:
7x - 9 = x^2+1 now do some algebra
0 = x^2 - 7x +10
0 = (x - 5)(x - 2)
x = +2, +5
2007-10-04 12:19:05
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answer #4
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answered by nyphdinmd 7
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It cant be solved by simultaneous equations, however, if you put them equal to each other...
x^2 + 1 = 7x - 9
You can bring them over and get a quadratic...
x^2 - 7x + 10
(x-5)(x-2)
Hence
x = 5 and x =2
2007-10-04 12:56:08
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answer #5
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answered by Anonymous
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x² + 1 = 7x - 9
x² - 7x + 10 = 0
(x - 5) (x - 2) = 0
x = 2 , x = 5
2007-10-04 15:42:30
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answer #6
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answered by Como 7
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y= 7x-9 y=7x
-9y=9(x^2)-9 -9y=9(x^2) wait... impossible. not evough numeric values to get an accurae answer
2007-10-04 16:13:45
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answer #7
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answered by Anonymous
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y=7x-9
y=x^2+1 (subract them)
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0=7x-x^2-10
change signs
x^2-7x+10=0
x^2-5x-2x+10=0
x(x-5)-2(x-5)=0
(x-5)(x-2)=0
x=5, x=2
if x=5, then for y
y= 7x-9
y=7(5)-9
y=35-9
y=26
if x=2, then for y
y= 7x-9
y=7(2)-9
y=14-9
y=5
2007-10-04 12:20:40
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answer #8
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answered by Siva 5
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