equilateral triangle sitting on the x-axis; what is its width at various heights as a function of y?

Answer 1

Let the base width be Wb. Then, by the length relations of a 30/60/90 triangle, the height of the triangle, H= (Wb/2)sqrt(3). Between the base and the max height, the width at any y, 0= Thus Wb/H = width/(Hb-y)=2/sqrt(3)