how much energy is needed to raise temperature?

Question

how much energy is needed to raise temperature of 0.6 kg of lead from 15 degrees celcius to 200 degrees celcius

Answer 1

Energy = change in temp * mass * specific heat

Do some subtraction to calculate temperature change
They give you mass
Go look up the specific heat of lead.
Plugnchug. Good luck.

Answer 2

You need to find the specific heat capacity of lead:

http://www.ausetute.com.au/heatcapa.html

It is 0.13 J K^-1 g^-1 [note that they give it in grams not kilograms, this means the mass in the next equation must be in grams]

You work out the energy required with the formula:

Energy = Mass * Change in temperature * specific heat capacity

In this case:

Energy = 600 grams * 185 degrees * 0.13 Specific Heat Capacity = 14430 Joules or 14.43 KJ.

Answer 3

there is gotta be a pretend effect if somebody stated it takes much less ability to kick back water than it does to warmth it. If a million gram of water is to alter temperature with the help of a million celsius degree, then it takes a million calorie to the two enter this water or to bypass away it. And the temp will fall or upward thrust counting on no count if that calorie got here or went. besides, the solar gives you particularly some ability to heat the sea as much as anybody could choose. The trick is to get that ability into the water. Carbon dioxide interior the ambience would possibly not seize adequate ability to boil the sea, inspite of the shown fact that it is not a great stretch to have faith that it could seize adequate ability to heat the sea greater suitable than we choose.

Answer 4

The heat required is given as 0.6*(200-15)*specific heat of lead which you must look up or I'm sure is there in the question.
Heat=m*c*t

Answer 5

According to a table at
http://en.wikipedia.org/wiki/Heat_capacity
the specific heat capacity per gram of lead is 3% that of liquid water.
(0.127 J/gK for lead versus 4.1813 for water).

Water's specific heat is 1 cal. per gram per degree K (or C, same interval) by the old definition.
0.6 kg is 600 g
15 C to 200 C is a difference of 185 degrees (C or K, same size intervals).

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So: direct method (using 0.127 Joules per gram and per degree, as found in the table):

600 grams times 185 degrees times 0.127 joules per gram and per degree; the grams and degrees cancel out, leaving only the Joules (a unit of energy).

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The indirect method (using the older units based on water)

To raise on gram of water by one degree is 1 cal. (by the old definition).
To raise one gram of lead by one degree is 1 cal. times 0.127/4.1813 = 0.0304 cal.
To raise 600 grams of lead by one degree is 0.0304 times 600 = 18.224 cal.
To raise 600 g of Pb by 185 degrees is 18.224 times 185.

The answer is in calories (small c)

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To check that both answers match, use 1 cal. = 4.1813 Joules (hey, where have we seen this number before?).