2007-10-04 00:45:53 · 8 answers · asked by . 1 in Science & Mathematics ➔ Mathematics
common denominator,
6x-15 - (5x/15) = 3
x/15 = 3
x=45
2007-10-04 00:50:55 · answer #1 · answered by Anonymous · 2⤊ 0⤋
2x / 5 - (x / 3) = 3 multiply 15 (lcd) to both sides of the equation.
[ 2x / 5 - (x / 3) = 3 ] 15
then,
3(2x) - 5(x) = 15(3)
6x - 5x = 45
therefore, x = 45.
CHECK:
substitute x = 45 in the given equation.
2(45) / 5 - (45 / 3) = 3
90 / 5 - 15 = 3
18 - 15 = 3
3 = 3.
2007-10-04 08:07:46 · answer #2 · answered by syaoran 2 · 1⤊ 0⤋
2x / 5 - (x / 3) = 3
=> x [ 2/5 - 1/3 ] = 3
=> x * 1/15 = 3
=> x = 45.
2007-10-04 08:15:38 · answer #3 · answered by Madhukar 7 · 1⤊ 0⤋
2x/5 -x/3=3
Multiplying both sides by 15,the LCM of 5 and 3,we get
15*2x/5 -15*x/3=15*3
6x-5x=45
x=45 ans
2007-10-04 07:52:23 · answer #4 · answered by alpha 7 · 1⤊ 0⤋
2x / 5 - (x / 3) = 3
LCD is 15.
Multiply both sides of the equation by 15.
6x - 5x = 45
x = 45
2007-10-04 07:56:30 · answer #5 · answered by edith p 3 · 1⤊ 0⤋
2x/5 -x/3=3
TAKE LCM
{2X(3)-X(5)}/(5*3)=3
(6X-5X)/15=3
X/15=3
X=45
2007-10-04 07:55:58 · answer #6 · answered by Mike 2 · 1⤊ 0⤋
6x/15 - (5x/15) = 3
x/15 = 3
45 = x
x = 45
2007-10-04 07:51:25 · answer #7 · answered by Anonymous · 1⤊ 0⤋
6x - 5x = 45
x = 45
2007-10-04 11:31:47 · answer #8 · answered by Como 7 · 0⤊ 3⤋