R=kpM^n
R=46.7
p=60
M=10
k and n are constants.
2007-10-03 22:23:03 · 5 answers · asked by bmxbandit23 2 in Science & Mathematics ➔ Mathematics
log R = log (kpM^n)
log R = log (kp) + log (M^n)
log R = log k + log p + n*log M
log k + n * log 10 = log R - log p
log k + n = log (R/p) = log (46.7/60)
2007-10-03 22:49:28 · answer #1 · answered by The K-Factor 3 · 0⤊ 0⤋
R = kpM^n
R/ kp = M^n
log(R/ kp) = log(M^n)
log(R/ kp) = n logM
log(R/ kp) / logM = n
log(R/ kp - M) = n
log(46â7/ k60 - 10) = n
log(0â778 33..(1/k) - 10) = n
n = log(0â778 33..(1/k) - 10)
2007-10-04 05:38:16 · answer #2 · answered by Sparks 6 · 0⤊ 0⤋
log 46.7 = log k + log 60 + n log10
2007-10-04 05:34:55 · answer #3 · answered by Fr3e@K3D 1 · 0⤊ 0⤋
log R = log k + log p + n log M
log 46.7 = log k + log 60 + n log 10
log 46.7 - log 60 = log k + log 10^n
log (46.7 / 60) = log (k 10^n)
46.7 / 60 = (k) (10^n)
2007-10-09 15:02:27 · answer #4 · answered by Como 7 · 2⤊ 0⤋
R=kpM^n
k=(pM^n)/R
p=(kM^n)/R
log(R/(kp))=n*log(M)
n = log(R/(kp))/log(M)
log(R/(kp))=n*log(M)
log(R/(kp))/n = log(M)
10^(og(R/(kp))/n) = M
2007-10-04 05:34:46 · answer #5 · answered by kimbokrn 2 · 0⤊ 0⤋