A pharmaceutical chemist runs a chromatography test on a substance and identifies two of its components by comparing their Rf values against certain standards. If the two components have Rf values of 1.0 and 0.41 and the solvent front has traveled 12.0 cm from the samples origin, what is the separation distance on the chromatogram??
2007-10-03 19:23:06 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
since Rf = travelled distance of substance i / travelled distance of standard.
so for substance 1 where Rf = 1 the distance that this substance had travelled was (1.0 x 12 cm) = 12 cm
for substance 2 where Rf = 0.41 the distance that this substance had travelled was (0.41 x 12 cm) = 4.92 cm
the separation distance of the two substances was = 12 - 4.92 = 7.08 cm
hope that would help!
2007-10-03 19:36:22 · answer #1 · answered by IonicLiquids 2 · 1⤊ 0⤋
12 - (0.41 x 12) cm.
2007-10-04 02:34:01 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋