what mass of silver will store 2000 calories of heat to allow 13.5C temp change?

Answer 1

I think you post only a fraction faster than I can answer, which should speak about how easy the problems you post are.

q = m x C x delta T
q = 2000 cal = 8368 J
C = 0.235 J/g°C
delta T = 13.5

m = q / (C x delta T) = 8368 / (0.235 x 13.5) = 2638 g

Answer 2

Ihvinny, why you are just solving this lazy guy homework? what do you want to prove? Stop answering like that and at least let him do the calculations.