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A child slides down a hill on a toboggan with an acceleration of 1.8 m/s^2.

If she starts at rest, how far has she traveled in 1.0 s?

I got 1.8 m but it was incorrect... how?

2007-10-03 17:40:13 · 3 answers · asked by Anonymous in Science & Mathematics Physics

3 answers

Because she started at zero. After 1.0 s she has reached a speed of 1.8 M/s. but has not been traveling at that speed the whole time. The outre folks gave you the math, I hope this is what you are looking for. For instance, after 0.5 s, she is only traveling at 0.9 M/s so could not possibly cover 1.8 M in one second.

2007-10-03 18:11:21 · answer #1 · answered by Charles C 7 · 0 0

Formula for distance covered, s, is
s = ut + (1/2)at^2, where u = initial velocity and a = acceleration.
Here, u = 0 and a = 1.8 m/s^2
So, s = 0 + (1/2)(1.8)(1^2)
= 0.9 m.

2007-10-03 17:50:10 · answer #2 · answered by Madhukar 7 · 0 0

d=vit+1/2at^2 we know vi is zero.

d=1/2(1.8)(1)^2

d=0.9m

2007-10-03 17:46:47 · answer #3 · answered by Anonymous · 0 0

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