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A box contains 3 yellow, 2 blue, and 4 red pencils. Suppose you choose a pencil, replace and choose another. find the probability of choosing yellow, then red.

2007-10-03 17:38:01 · 4 answers · asked by Ms. LAN 1 in Science & Mathematics Mathematics

4 answers

P = (3 / 9) (4 / 9) = 12 / 81 = 4 / 27

2007-10-03 22:13:59 · answer #1 · answered by Como 7 · 2 2

the probability of drawing a yellow first is 3/9
the probability of drawing a red second, given replacement of the first pencil, is 4/9

the two events are independent and therefore you can multiply the two probabilities together to get the solution.

P(yellow then red pencil) = 3/9 * 4/9 = 12/81 = 0.1481481

2007-10-04 19:11:26 · answer #2 · answered by Merlyn 7 · 0 2

P(yellow) = 3/9
P(Red) = 4/9

required probabilty is 3/9 * 4/9 = 12/81

2007-10-03 17:43:23 · answer #3 · answered by unknown123 2 · 0 1

3 yellow + 2 blue + 4 red = 9 (colored) pencils
First draw: Yellow (3/9)=(1/3)
Second draw:Red (4/9)
Combined Probability: P(A^B)=P(A)P(B)
(1/3)(4/9)=4/27

2007-10-03 17:49:57 · answer #4 · answered by "Steve Jobs" 3 · 0 2

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