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A sample of benzene, c6h6 contains 3.0 * 10 to the power of 23 molecules of benzene. how many grams are in the sample?

2007-10-03 15:29:23 · 5 answers · asked by Anonymous in Science & Mathematics Chemistry

5 answers

Since a mole of any compound/element contains 6.02 x 10^23 molecules/atoms you can calculate as follows:

3.0 x 10^23 molecules/6.02 x 10^23 molecules/mol x

78g/mole = 38.9g

2007-10-03 15:36:20 · answer #1 · answered by Flying Dragon 7 · 1 0

C6H6 has a molar mass of 6(12.01) + 6(1.01) g/mole
= 78.12 g/mole
3.0 x 10^23 molecules =
(3.0 x 10^23)(1/(6.022 x 10^23)) moles

So the number of grams in 3.0 x 10^23 molecules of
benzene =
[(3.0 x 10^23)(1/(6.022 x 10^23)) moles][78.12 g/mole]

= 39 g

2007-10-03 22:38:03 · answer #2 · answered by Marvin 4 · 0 0

1 mole of benzene has 6.02 x 10^23 molecules in it. Benzene has a Formula Weight of 78.11, so 1 mole of Benzene is 78.11 grams. (Remember, FW = grams / mole), so you have 3.0 x 10^23, which is 1/2 a mole of Benzene. So the number of grams is equal to 78.11 divided by 2 = 39.06 grams.

2007-10-03 22:48:33 · answer #3 · answered by Anonymous · 0 0

Use Avogadro's number for this problem:

3.0*10^23 molecules x (1mol/6.022^23 molecules) x (78.11g C6H6/1mol C6H6) = 38.91 g C6H6

Good luck!

2007-10-03 22:59:12 · answer #4 · answered by tinhmay 1 · 0 0

(3.0E6molecules/6.023E23molecules)* (54 g of C6H6)

so when you plug these value in to ur calculate, you should get
answer = 2.68*10^(-12) grams

2007-10-03 22:34:41 · answer #5 · answered by ron1999 2 · 0 0

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