its a right triangle, so the diagonal is your c², and since it is a square, all sides are the same, so a² + b² = c². So take 5, square it and devide that by 2, and then take the square root of that. that will give you the length of one side. Whatever # you get, mulitply that by 4 for your perimiter
2007-10-03 15:11:36
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answer #1
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answered by m.pasciucco 1
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hi
your question is going to be answered with the Pythagoras theory.
to find the perimeter of a square, you need the length of the sides. in square, all sides are equal. now keep it in your mind...
in the Pythagoras theory, a2+ b2=c2 (numbers are the exponents)
a,b, and c are the sides of a right triangle which is half of a square. a and b are the sides and c is the diagonal which is 5. so ==> 5(2)= a(2) + b(2) numbers in the brackets are the exponents. because it is square and all sides are equal, then a=b so ==> 5(2)= 2x(2) ==>25=2x(2)
then you divide both sides by 2 because it is the coefficient of the x. ==> 25/2==>x(2) ==> 12.5 =x(2)
now to find x, you have to put both sides under the radical ==>
square root of 12.5 is 3.53 and sq rt of x(2) is x
so==> x=3.53 which is the length of one side.
to get the perimeter of a square, you have to multiply a side times 4 so 3.53 cm * 4= 14.12cm (don't forget the numbers in the brackets are exponents)
2007-10-03 22:28:15
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answer #2
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answered by Emad $h 1
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Perimeter of a square = 4 x side length
let x = length of side of your square
Perimeter = 4x
The diagonal is the hypotenuse of a right triangle with the two legs being the sides of the square.
Pathagorean theorum says:
5^2 = x^2 + x^2
25 = 2x^2
x = 3.53
perimeter = 14.14 (approximately)
2007-10-03 22:12:42
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answer #3
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answered by lhvinny 7
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the diagonal of a square with sides = 1 is the square root of 2 = 1.414. divide 5/1.414 = 3.536 for the sides
3.536*4 = 14.144
2007-10-03 22:21:02
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answer #4
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answered by Info_Please 4
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the side would be 1.58
so perimeter= 4 x 1.58= 6.32
2007-10-03 22:17:22
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answer #5
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answered by sayamaunanyadonk 1
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