Two circular loops of wire with a common center?

Question

Two circular loops of wire, each containing a single turn, have the same radius of 9.71 cm and a common center. The planes of the loops are perpendicular. each carries a current of 6.84 A. What is the magnitude of the net magnetic field at the common center?

Lost, any help would be appreciated. Thanks

Would I just use
B = (1.257e-6)(6.84)/2(3.14)(.0971)

And then multiply it by 2 to get 2.82e-5?

Answer 1

Use the same equation needed for your other question. That chapter you need to read has a lot to say about it.

Answer 2

each loop provides a magnetic field this is prevalent to the loop. for the reason that the two loops are perpendicular to one yet another, so too would be their guy or woman contributions to the magnetic field. because of fact the loops are in any different case comparable, what you have is two equivalent magnetic fields, perpendicular to one yet another, including vectorially. So the magnitude is sqrt(2) x the magnitude of the two one in my view. this is the "cleverness" area of the priority. the person-friendly area is: What replaced into the magnitude of the loops in my view? that's: B = µ0*contemporary/(2*radius), as shown interior the reference.