A Little Physics Help, please!?

Question

A car is traveling at 58.0 km/h on a flat highway. If the coefficient of friction between road and tires on a rainy day is 0.100, what is the minimum distance in which the car will stop?

I thought i needed mass to find the coefficient, but the problem doesn't give it...

Answer 1

The kinetic energy of the car becomes say friction work done

Ke=Wf
Ke=0.5 mV^2 and
Wf= u mg d

u - coefficient of friction
m - mass
g - acceleration due to gravity
d - stopping distance

we have

0.5 mV^2 = u mg d

and finally

d= V^2 /( 2 u g)
d=(58)^2/( 2 x 0.100 x 9.81)
d=1720 m (This way too far)