w^3+5w^2-w=5?

0 ⤊

2007-10-03 13:38:45 · 2 answers · asked by Pep C 1 in Science & Mathematics ➔ Mathematics

2 answers

w³+ 5w² - w - 5 = 0
Using synthetic division:-
1|1__5__-1___-5
"|___1__6____5
"|1__6__5____0
R = 0 shows that w - 1 is a factor
(w - 1)( w ² + 6 w + 5) = 0
(w - 1)(w + 5)(w + 1) = 0
w = 1 , w = - 5 , w = - 1

2007-10-07 11:38:26 · answer #1 · answered by Como 7 · 0⤊ 0⤋

w^3 + 5w^2 - w - 5 = 0

(w + 5)(w + 1)(w - 1) = 0

w1 = -5
w2 = -1
w3 = 1

2007-10-03 13:51:10 · answer #2 · answered by Seto 2 · 0⤊ 0⤋