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How many grams of Mg metal can be produced in 3.00 h using a current of 47.0 amps to electrolyze molten magnesium chloride?

2007-10-03 13:13:37 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

A current of 47.0 amps for 3.00 h is (47*3*3600) C (coulomb). Oxidation number of Mg++ is 2. Thus (47*3*3600)/(2*96485) is the number of Mole of Mg can be produced. The atomic mass of Mg is 24.305g. Hence the answer is: 24.305g x (47*3*3600)/(2*96485) = 63.9 g

2007-10-05 11:00:56 · answer #1 · answered by Hahaha 7 · 0 0

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