There this question that has been on the quiz for a couple of time..and i miss it all the time. Please help and explain how can i solve these kind of problem.
An adult pass for a country fair cost $2 more than a children pass. When 378 adult and 214 children passes were sold, the total revenue was $2384. Find the cost of an adult pass.
2007-10-03 13:12:38 · 3 answers · asked by yue 1 in Science & Mathematics ➔ Mathematics
let x = price of child ticket
let (x+2) = price of adult ticket
equations:
378 [# of adults] X (x+2)[price] + 214 [#of kids] X x = 2384
simplified
378(x+2) + 214x = 2384
distribute
378x + 756 +214x = 2384
combine like terms
592x = 1628
divide by 592
x = $2.75
remember x = child's ticket
x+2 = adult's ticket
2.75 + 2 = $4.75 = adult's ticket
2007-10-03 13:19:59 · answer #1 · answered by dogbitte 2 · 1⤊ 1⤋
Set up the equation this way... and you will see how this makes sense. (n=price)
378(n+2) +214(n) = 2384
solve for n
n= 2.75 so... the adult pass in n+2. therefore the adult pass costs $4.75
2007-10-03 13:19:25 · answer #2 · answered by Danny 2 · 1⤊ 1⤋
cost of adult pass = a
cost of child pass = c
c = a - 2
378a + 214c = 2384
378a + 214(a - 2) = 378a + 214a - 428 = 592a -428 = 2384
592a = 2812
a = 4.75
2007-10-03 13:23:29 · answer #3 · answered by Beardo 7 · 1⤊ 1⤋