question is in details ( projectile motion)?

Question

a ball is launched at 30angle above horizontal. what launch speed is required so that the kiwi will land in basket 35 meters distant across level ground

Answer 1

A kiwi or a ball?

No matter:

x(t)=v*cos(30)*t
and
vy(t)=v*sin(30)-g*t

the time to apogee, vy(t)=0 is half the flight time to the basket.

v*sin(30)/g=t
v^2*2*sin(30)*cos(30)/g=35
since 2*sin(30)*cos(30)=sin(60)
v=sqrt(35*g/sin(60))

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Answer 2

"The ball is suffering from air resistance." it rather is a mandatory component of the question. no longer really does this mean that the horizontal component of the suitable fee will drop to 0, yet this also ability that, for the era of its fall, the ball will at very last attain its terminal speed. it rather is by way of very truth the rigidity of air drag because of its speed in the direction of earth negates the rigidity of gravity, meaning there is not any internet rigidity and no internet acceleration.