Suppose that 'f' is a function with f(-3)=1 and f ' (-3)=6. If h(x)=(f(x)^3)^1/2 then h ' (-3)=?

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I need h ' (-3).

2007-10-03 12:24:14 · 2 answers · asked by jtaylor 1 in Science & Mathematics ➔ Mathematics

If h(x) = f(x)^(3/2), then h'(x) = (3/2)*[f(x)^1/2]*f'(x).

Now use the known values you listed to find h'(-3).

2007-10-03 12:28:07 · answer #1 · answered by Mathsorcerer 7 · 0⤊ 0⤋

h'(x) = (3/2) * (f²(x) * f'(x)) / sqrt(f³(x))
h'(-3) = (3/2) * (1² * 6) / sqrt(1³) = 9

2007-10-03 12:30:13 · answer #2 · answered by Mαtt 6 · 0⤊ 0⤋