2007-10-03 12:08:57 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
If the mutant gene is recessive, it will not manifest itself in individuals with only one copy, who will be carriers. Two carriers would have a 1/4 chance of having an offspring with the recessive mutant gene expressed, 1/2 chance of having carriers (unexpressed mutant gene) and 1/4 chance of having an offspring without the mutant gene.
2007-10-03 12:13:43 · answer #1 · answered by Vincent G 7 · 0⤊ 1⤋
How are mutant genes selectively destroyed?
All evolutionary advancements (in any species) have been the result of genetic mutations that survived and were passed on to offspring.
While some mutations may not be viable in the organism (and therefore the organism doesn't survive to reproduce), there are as many advantageous mutations that do survive and reproduce.
2007-10-03 12:15:04 · answer #2 · answered by Anonymous · 0⤊ 0⤋
They convey a slight competitive advantage, or first cousins keep on marrying one another.
2007-10-03 12:14:36 · answer #3 · answered by steve_geo1 7 · 0⤊ 0⤋
if the changes are subtle, then they can last for several cell cycles before detection, and by then it could be too late.
2007-10-03 12:15:15 · answer #4 · answered by A Person 2 · 0⤊ 1⤋